Izindaba

Lapho iZonel Filtech isiza amakhasimende ukuthi athuthukise abaqoqi bawo uthuli, abanye babo bakhononda ngokuthi izinhlelo zokuhlanzaizindlu zokuhlunga isikhwamaayisebenzi kahle ngisho noma zisebenzisa ipayipi eliholayo emoyeni epayipini elivuthela umoya, kanye ne-venturi, kanye nengcindezi efanele yomoya ocindezelwe, ngakho abakwazi ukuthola isisombululo sokuthuthukisa imisebenzi yokuhlanza.

Ngemva kokuhlaziya uhlelo lwabo lokuhlanza, onjiniyela beZonel bathola isizathu esiyinhloko ukuthi ibanga eliphakathi kwepayipi eliholela emoyeni kuya eshidini leshubhu yesikhwama alilungile. Uma ibanga likhulu kakhulu, umoya ungase uphephethe okunye eshidini leshubhu lesikhwama esikhundleni sezikhwama zokuhlunga; ngokuphambene nalokho, uma umncane kakhulu, umoya ocindezelwe awukwazi ukuholela umoya owanele ngaphandle ezikhwameni zokuhlunga, umphumela wokuhlanza ngokuqinisekile ngeke ube muhle.

Kodwa indlela yokuchaza leli banga (H1 emdwebeni olandelayo)?

１.Isinyathelo sokuqala, udinga ukuchaza inani elimaphakathi le-Øp emdwebeni.
Njengenjwayelo, sibala i-Øp ngefomula elandelayo:
Øp=(C*D^2/n) ^1/2
C=I-Coefficient, njengenjwayelo khetha 50%~65%.
D=i-pulse jet valve outlet diameter, njengokujwayelekile okufanayo nasepayipini elifutha umoya.
n=inombolo yesikhwama sokuhlunga umugqa ngamunye (ukuhlanza nge-valve yejethi ye-pulse efanayo)
Njengenjwayelo, C sikhetha 0.55.
Ikakhulukazi, ipayipi lomoya eliholayo ubukhulu yizikhathi ezingu-2~3 ze-Øp.

 

２.Chaza ubude bepayipi elihola umoya.
Ipayipi elihola umoya njengokujwayelekile sebenzisa ifomula elandelayo:
L=Ck* Øp/K
Ck=i-coefficient, njengenjwayelo khetha 0.2~0.25
K=i-jet turbulence coefficient, i-cylindrical khetha 0.076.
okungukuthi L= cishe 0.2* Øp/0.076=2.65 Øp

 

３.Kulula kakhulu ukuthola leyo tg a degree =(1/2 Øb)/H2
tg a degree= 3.4K=0.272 (ingaphathwa njengokungaguquki)
Ngakho-ke idigri khetha i-15 degree.

 

Ngokwesibonelo:
Uma ukhetha i-valve yejethi ye-pulse egxilile engu-3”, ipayipi eliholayo d=30mm, ububanzi besikhwama sokuhlunga ngu-160mm, uyithola kanjani i-H1.
Impendulo:
Ngokusobala, i-H1=H2-L
Ngakho-ke kufanele sichaze i-H2 ne-L.

tg idigri =(1/2 Øb)/H2=3.4K=0.272
okungukuthi H2=1.838 Øb

Øb = 160mm
Ngakho i-H2=294 mm

3”njengokuvamile isilinganiso esingu-Øp=15 mm (futhi singabala ukuthi isikhwama sinikezwa nini, noma ngokuya ngedatha yolwazi, yengezwe sicela uthole.)
Kusukela kumphumela wangaphambilini, L=2.65 Øp, ngakho-ke i-L=2.65*15=40 mm
Ngakho i-H1=294-40=254mm.

 

Ku-Qp, ngokuvamile idatha emaphakathi ingakhethwa njengokulandelayo:
I-Pulse jet valve size ---- Qp
3/4"----5~7mm
1” ---- 6~8mm
1 1/2"----7~9mm
2"----8~11mm
2 1/2"----9~14mm
3"----14 ~ 18mm
4"----16~22mm

 

Njengenjwayelo, lapho idizayini ye-Qp izohlukaniswa ngamaqembu angu-3~4, eduze ne-valve yejet ye-pulse, usayizi ovulekile omkhulu, futhi iqembu liqoqe umehluko wobubanzi obungaba ngu-1mm.